3.135 \(\int \frac{x^4 (c+d x^2+e x^4+f x^6)}{(a+b x^2)^3} \, dx\)

Optimal. Leaf size=207 \[ \frac{x^5 \left (c-\frac{a \left (a^2 f-a b e+b^2 d\right )}{b^3}\right )}{4 a \left (a+b x^2\right )^2}-\frac{x \left (9 a^2 b e-13 a^3 f-5 a b^2 d+b^3 c\right )}{8 b^5 \left (a+b x^2\right )}-\frac{x \left (13 a^2 b e-25 a^3 f-5 a b^2 d+b^3 c\right )}{4 a b^5}+\frac{\tan ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{a}}\right ) \left (35 a^2 b e-63 a^3 f-15 a b^2 d+3 b^3 c\right )}{8 \sqrt{a} b^{11/2}}+\frac{x^3 (b e-3 a f)}{3 b^4}+\frac{f x^5}{5 b^3} \]

[Out]

-((b^3*c - 5*a*b^2*d + 13*a^2*b*e - 25*a^3*f)*x)/(4*a*b^5) + ((b*e - 3*a*f)*x^3)/(3*b^4) + (f*x^5)/(5*b^3) + (
(c - (a*(b^2*d - a*b*e + a^2*f))/b^3)*x^5)/(4*a*(a + b*x^2)^2) - ((b^3*c - 5*a*b^2*d + 9*a^2*b*e - 13*a^3*f)*x
)/(8*b^5*(a + b*x^2)) + ((3*b^3*c - 15*a*b^2*d + 35*a^2*b*e - 63*a^3*f)*ArcTan[(Sqrt[b]*x)/Sqrt[a]])/(8*Sqrt[a
]*b^(11/2))

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Rubi [A]  time = 0.333674, antiderivative size = 207, normalized size of antiderivative = 1., number of steps used = 6, number of rules used = 5, integrand size = 30, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.167, Rules used = {1804, 1585, 1257, 1810, 205} \[ \frac{x^5 \left (c-\frac{a \left (a^2 f-a b e+b^2 d\right )}{b^3}\right )}{4 a \left (a+b x^2\right )^2}-\frac{x \left (9 a^2 b e-13 a^3 f-5 a b^2 d+b^3 c\right )}{8 b^5 \left (a+b x^2\right )}-\frac{x \left (13 a^2 b e-25 a^3 f-5 a b^2 d+b^3 c\right )}{4 a b^5}+\frac{\tan ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{a}}\right ) \left (35 a^2 b e-63 a^3 f-15 a b^2 d+3 b^3 c\right )}{8 \sqrt{a} b^{11/2}}+\frac{x^3 (b e-3 a f)}{3 b^4}+\frac{f x^5}{5 b^3} \]

Antiderivative was successfully verified.

[In]

Int[(x^4*(c + d*x^2 + e*x^4 + f*x^6))/(a + b*x^2)^3,x]

[Out]

-((b^3*c - 5*a*b^2*d + 13*a^2*b*e - 25*a^3*f)*x)/(4*a*b^5) + ((b*e - 3*a*f)*x^3)/(3*b^4) + (f*x^5)/(5*b^3) + (
(c - (a*(b^2*d - a*b*e + a^2*f))/b^3)*x^5)/(4*a*(a + b*x^2)^2) - ((b^3*c - 5*a*b^2*d + 9*a^2*b*e - 13*a^3*f)*x
)/(8*b^5*(a + b*x^2)) + ((3*b^3*c - 15*a*b^2*d + 35*a^2*b*e - 63*a^3*f)*ArcTan[(Sqrt[b]*x)/Sqrt[a]])/(8*Sqrt[a
]*b^(11/2))

Rule 1804

Int[(Pq_)*((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^2)^(p_), x_Symbol] :> With[{Q = PolynomialQuotient[Pq, a + b*x
^2, x], f = Coeff[PolynomialRemainder[Pq, a + b*x^2, x], x, 0], g = Coeff[PolynomialRemainder[Pq, a + b*x^2, x
], x, 1]}, Simp[((c*x)^m*(a + b*x^2)^(p + 1)*(a*g - b*f*x))/(2*a*b*(p + 1)), x] + Dist[c/(2*a*b*(p + 1)), Int[
(c*x)^(m - 1)*(a + b*x^2)^(p + 1)*ExpandToSum[2*a*b*(p + 1)*x*Q - a*g*m + b*f*(m + 2*p + 3)*x, x], x], x]] /;
FreeQ[{a, b, c}, x] && PolyQ[Pq, x] && LtQ[p, -1] && GtQ[m, 0]

Rule 1585

Int[(u_.)*(x_)^(m_.)*((a_.)*(x_)^(p_.) + (b_.)*(x_)^(q_.) + (c_.)*(x_)^(r_.))^(n_.), x_Symbol] :> Int[u*x^(m +
n*p)*(a + b*x^(q - p) + c*x^(r - p))^n, x] /; FreeQ[{a, b, c, m, p, q, r}, x] && IntegerQ[n] && PosQ[q - p] &
& PosQ[r - p]

Rule 1257

Int[(x_)^(m_.)*((d_) + (e_.)*(x_)^2)^(q_)*((a_) + (b_.)*(x_)^2 + (c_.)*(x_)^4)^(p_.), x_Symbol] :> Simp[((-d)^
(m/2 - 1)*(c*d^2 - b*d*e + a*e^2)^p*x*(d + e*x^2)^(q + 1))/(2*e^(2*p + m/2)*(q + 1)), x] + Dist[1/(2*e^(2*p +
m/2)*(q + 1)), Int[(d + e*x^2)^(q + 1)*ExpandToSum[Together[(1*(2*e^(2*p + m/2)*(q + 1)*x^m*(a + b*x^2 + c*x^4
)^p - (-d)^(m/2 - 1)*(c*d^2 - b*d*e + a*e^2)^p*(d + e*(2*q + 3)*x^2)))/(d + e*x^2)], x], x], x] /; FreeQ[{a, b
, c, d, e}, x] && NeQ[b^2 - 4*a*c, 0] && IGtQ[p, 0] && ILtQ[q, -1] && IGtQ[m/2, 0]

Rule 1810

Int[(Pq_)*((a_) + (b_.)*(x_)^2)^(p_.), x_Symbol] :> Int[ExpandIntegrand[Pq*(a + b*x^2)^p, x], x] /; FreeQ[{a,
b}, x] && PolyQ[Pq, x] && IGtQ[p, -2]

Rule 205

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(Rt[a/b, 2]*ArcTan[x/Rt[a/b, 2]])/a, x] /; FreeQ[{a, b}, x]
&& PosQ[a/b]

Rubi steps

\begin{align*} \int \frac{x^4 \left (c+d x^2+e x^4+f x^6\right )}{\left (a+b x^2\right )^3} \, dx &=\frac{\left (c-\frac{a \left (b^2 d-a b e+a^2 f\right )}{b^3}\right ) x^5}{4 a \left (a+b x^2\right )^2}-\frac{\int \frac{x^3 \left (\left (b c-5 a d+\frac{5 a^2 e}{b}-\frac{5 a^3 f}{b^2}\right ) x-4 a \left (e-\frac{a f}{b}\right ) x^3-4 a f x^5\right )}{\left (a+b x^2\right )^2} \, dx}{4 a b}\\ &=\frac{\left (c-\frac{a \left (b^2 d-a b e+a^2 f\right )}{b^3}\right ) x^5}{4 a \left (a+b x^2\right )^2}-\frac{\int \frac{x^4 \left (b c-5 a d+\frac{5 a^2 e}{b}-\frac{5 a^3 f}{b^2}-4 a \left (e-\frac{a f}{b}\right ) x^2-4 a f x^4\right )}{\left (a+b x^2\right )^2} \, dx}{4 a b}\\ &=\frac{\left (c-\frac{a \left (b^2 d-a b e+a^2 f\right )}{b^3}\right ) x^5}{4 a \left (a+b x^2\right )^2}-\frac{\left (b^3 c-5 a b^2 d+9 a^2 b e-13 a^3 f\right ) x}{8 b^5 \left (a+b x^2\right )}+\frac{\int \frac{a \left (b^3 c-5 a b^2 d+9 a^2 b e-13 a^3 f\right )-2 b \left (b^3 c-5 a b^2 d+9 a^2 b e-13 a^3 f\right ) x^2+8 a b^2 (b e-2 a f) x^4+8 a b^3 f x^6}{a+b x^2} \, dx}{8 a b^5}\\ &=\frac{\left (c-\frac{a \left (b^2 d-a b e+a^2 f\right )}{b^3}\right ) x^5}{4 a \left (a+b x^2\right )^2}-\frac{\left (b^3 c-5 a b^2 d+9 a^2 b e-13 a^3 f\right ) x}{8 b^5 \left (a+b x^2\right )}+\frac{\int \left (-2 \left (b^3 c-5 a b^2 d+13 a^2 b e-25 a^3 f\right )+8 a b (b e-3 a f) x^2+8 a b^2 f x^4+\frac{3 a b^3 c-15 a^2 b^2 d+35 a^3 b e-63 a^4 f}{a+b x^2}\right ) \, dx}{8 a b^5}\\ &=-\frac{\left (b^3 c-5 a b^2 d+13 a^2 b e-25 a^3 f\right ) x}{4 a b^5}+\frac{(b e-3 a f) x^3}{3 b^4}+\frac{f x^5}{5 b^3}+\frac{\left (c-\frac{a \left (b^2 d-a b e+a^2 f\right )}{b^3}\right ) x^5}{4 a \left (a+b x^2\right )^2}-\frac{\left (b^3 c-5 a b^2 d+9 a^2 b e-13 a^3 f\right ) x}{8 b^5 \left (a+b x^2\right )}+\frac{\left (3 b^3 c-15 a b^2 d+35 a^2 b e-63 a^3 f\right ) \int \frac{1}{a+b x^2} \, dx}{8 b^5}\\ &=-\frac{\left (b^3 c-5 a b^2 d+13 a^2 b e-25 a^3 f\right ) x}{4 a b^5}+\frac{(b e-3 a f) x^3}{3 b^4}+\frac{f x^5}{5 b^3}+\frac{\left (c-\frac{a \left (b^2 d-a b e+a^2 f\right )}{b^3}\right ) x^5}{4 a \left (a+b x^2\right )^2}-\frac{\left (b^3 c-5 a b^2 d+9 a^2 b e-13 a^3 f\right ) x}{8 b^5 \left (a+b x^2\right )}+\frac{\left (3 b^3 c-15 a b^2 d+35 a^2 b e-63 a^3 f\right ) \tan ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{a}}\right )}{8 \sqrt{a} b^{11/2}}\\ \end{align*}

Mathematica [A]  time = 0.159392, size = 176, normalized size = 0.85 \[ \frac{x \left (a^2 b^2 \left (225 d-875 e x^2+504 f x^4\right )-525 a^3 b \left (e-3 f x^2\right )+945 a^4 f-a b^3 \left (45 c-375 d x^2+280 e x^4+72 f x^6\right )+b^4 x^2 \left (8 \left (15 d x^2+5 e x^4+3 f x^6\right )-75 c\right )\right )}{120 b^5 \left (a+b x^2\right )^2}+\frac{\tan ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{a}}\right ) \left (35 a^2 b e-63 a^3 f-15 a b^2 d+3 b^3 c\right )}{8 \sqrt{a} b^{11/2}} \]

Antiderivative was successfully verified.

[In]

Integrate[(x^4*(c + d*x^2 + e*x^4 + f*x^6))/(a + b*x^2)^3,x]

[Out]

(x*(945*a^4*f - 525*a^3*b*(e - 3*f*x^2) + a^2*b^2*(225*d - 875*e*x^2 + 504*f*x^4) - a*b^3*(45*c - 375*d*x^2 +
280*e*x^4 + 72*f*x^6) + b^4*x^2*(-75*c + 8*(15*d*x^2 + 5*e*x^4 + 3*f*x^6))))/(120*b^5*(a + b*x^2)^2) + ((3*b^3
*c - 15*a*b^2*d + 35*a^2*b*e - 63*a^3*f)*ArcTan[(Sqrt[b]*x)/Sqrt[a]])/(8*Sqrt[a]*b^(11/2))

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Maple [A]  time = 0.013, size = 294, normalized size = 1.4 \begin{align*}{\frac{f{x}^{5}}{5\,{b}^{3}}}-{\frac{a{x}^{3}f}{{b}^{4}}}+{\frac{{x}^{3}e}{3\,{b}^{3}}}+6\,{\frac{{a}^{2}fx}{{b}^{5}}}-3\,{\frac{aex}{{b}^{4}}}+{\frac{dx}{{b}^{3}}}+{\frac{17\,{x}^{3}{a}^{3}f}{8\,{b}^{4} \left ( b{x}^{2}+a \right ) ^{2}}}-{\frac{13\,{x}^{3}{a}^{2}e}{8\,{b}^{3} \left ( b{x}^{2}+a \right ) ^{2}}}+{\frac{9\,a{x}^{3}d}{8\,{b}^{2} \left ( b{x}^{2}+a \right ) ^{2}}}-{\frac{5\,{x}^{3}c}{8\,b \left ( b{x}^{2}+a \right ) ^{2}}}+{\frac{15\,f{a}^{4}x}{8\,{b}^{5} \left ( b{x}^{2}+a \right ) ^{2}}}-{\frac{11\,{a}^{3}ex}{8\,{b}^{4} \left ( b{x}^{2}+a \right ) ^{2}}}+{\frac{7\,{a}^{2}dx}{8\,{b}^{3} \left ( b{x}^{2}+a \right ) ^{2}}}-{\frac{3\,acx}{8\,{b}^{2} \left ( b{x}^{2}+a \right ) ^{2}}}-{\frac{63\,{a}^{3}f}{8\,{b}^{5}}\arctan \left ({bx{\frac{1}{\sqrt{ab}}}} \right ){\frac{1}{\sqrt{ab}}}}+{\frac{35\,{a}^{2}e}{8\,{b}^{4}}\arctan \left ({bx{\frac{1}{\sqrt{ab}}}} \right ){\frac{1}{\sqrt{ab}}}}-{\frac{15\,ad}{8\,{b}^{3}}\arctan \left ({bx{\frac{1}{\sqrt{ab}}}} \right ){\frac{1}{\sqrt{ab}}}}+{\frac{3\,c}{8\,{b}^{2}}\arctan \left ({bx{\frac{1}{\sqrt{ab}}}} \right ){\frac{1}{\sqrt{ab}}}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^4*(f*x^6+e*x^4+d*x^2+c)/(b*x^2+a)^3,x)

[Out]

1/5*f*x^5/b^3-1/b^4*x^3*a*f+1/3/b^3*x^3*e+6/b^5*a^2*f*x-3/b^4*a*e*x+1/b^3*d*x+17/8/b^4/(b*x^2+a)^2*x^3*a^3*f-1
3/8/b^3/(b*x^2+a)^2*x^3*a^2*e+9/8/b^2/(b*x^2+a)^2*x^3*a*d-5/8/b/(b*x^2+a)^2*x^3*c+15/8/b^5/(b*x^2+a)^2*a^4*f*x
-11/8/b^4/(b*x^2+a)^2*a^3*e*x+7/8/b^3/(b*x^2+a)^2*a^2*d*x-3/8/b^2/(b*x^2+a)^2*a*c*x-63/8/b^5/(a*b)^(1/2)*arcta
n(b*x/(a*b)^(1/2))*a^3*f+35/8/b^4/(a*b)^(1/2)*arctan(b*x/(a*b)^(1/2))*a^2*e-15/8/b^3/(a*b)^(1/2)*arctan(b*x/(a
*b)^(1/2))*a*d+3/8/b^2/(a*b)^(1/2)*arctan(b*x/(a*b)^(1/2))*c

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Maxima [F(-2)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^4*(f*x^6+e*x^4+d*x^2+c)/(b*x^2+a)^3,x, algorithm="maxima")

[Out]

Exception raised: ValueError

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Fricas [A]  time = 1.3148, size = 1362, normalized size = 6.58 \begin{align*} \left [\frac{48 \, a b^{5} f x^{9} + 16 \,{\left (5 \, a b^{5} e - 9 \, a^{2} b^{4} f\right )} x^{7} + 16 \,{\left (15 \, a b^{5} d - 35 \, a^{2} b^{4} e + 63 \, a^{3} b^{3} f\right )} x^{5} - 50 \,{\left (3 \, a b^{5} c - 15 \, a^{2} b^{4} d + 35 \, a^{3} b^{3} e - 63 \, a^{4} b^{2} f\right )} x^{3} + 15 \,{\left (3 \, a^{2} b^{3} c - 15 \, a^{3} b^{2} d + 35 \, a^{4} b e - 63 \, a^{5} f +{\left (3 \, b^{5} c - 15 \, a b^{4} d + 35 \, a^{2} b^{3} e - 63 \, a^{3} b^{2} f\right )} x^{4} + 2 \,{\left (3 \, a b^{4} c - 15 \, a^{2} b^{3} d + 35 \, a^{3} b^{2} e - 63 \, a^{4} b f\right )} x^{2}\right )} \sqrt{-a b} \log \left (\frac{b x^{2} + 2 \, \sqrt{-a b} x - a}{b x^{2} + a}\right ) - 30 \,{\left (3 \, a^{2} b^{4} c - 15 \, a^{3} b^{3} d + 35 \, a^{4} b^{2} e - 63 \, a^{5} b f\right )} x}{240 \,{\left (a b^{8} x^{4} + 2 \, a^{2} b^{7} x^{2} + a^{3} b^{6}\right )}}, \frac{24 \, a b^{5} f x^{9} + 8 \,{\left (5 \, a b^{5} e - 9 \, a^{2} b^{4} f\right )} x^{7} + 8 \,{\left (15 \, a b^{5} d - 35 \, a^{2} b^{4} e + 63 \, a^{3} b^{3} f\right )} x^{5} - 25 \,{\left (3 \, a b^{5} c - 15 \, a^{2} b^{4} d + 35 \, a^{3} b^{3} e - 63 \, a^{4} b^{2} f\right )} x^{3} + 15 \,{\left (3 \, a^{2} b^{3} c - 15 \, a^{3} b^{2} d + 35 \, a^{4} b e - 63 \, a^{5} f +{\left (3 \, b^{5} c - 15 \, a b^{4} d + 35 \, a^{2} b^{3} e - 63 \, a^{3} b^{2} f\right )} x^{4} + 2 \,{\left (3 \, a b^{4} c - 15 \, a^{2} b^{3} d + 35 \, a^{3} b^{2} e - 63 \, a^{4} b f\right )} x^{2}\right )} \sqrt{a b} \arctan \left (\frac{\sqrt{a b} x}{a}\right ) - 15 \,{\left (3 \, a^{2} b^{4} c - 15 \, a^{3} b^{3} d + 35 \, a^{4} b^{2} e - 63 \, a^{5} b f\right )} x}{120 \,{\left (a b^{8} x^{4} + 2 \, a^{2} b^{7} x^{2} + a^{3} b^{6}\right )}}\right ] \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^4*(f*x^6+e*x^4+d*x^2+c)/(b*x^2+a)^3,x, algorithm="fricas")

[Out]

[1/240*(48*a*b^5*f*x^9 + 16*(5*a*b^5*e - 9*a^2*b^4*f)*x^7 + 16*(15*a*b^5*d - 35*a^2*b^4*e + 63*a^3*b^3*f)*x^5
- 50*(3*a*b^5*c - 15*a^2*b^4*d + 35*a^3*b^3*e - 63*a^4*b^2*f)*x^3 + 15*(3*a^2*b^3*c - 15*a^3*b^2*d + 35*a^4*b*
e - 63*a^5*f + (3*b^5*c - 15*a*b^4*d + 35*a^2*b^3*e - 63*a^3*b^2*f)*x^4 + 2*(3*a*b^4*c - 15*a^2*b^3*d + 35*a^3
*b^2*e - 63*a^4*b*f)*x^2)*sqrt(-a*b)*log((b*x^2 + 2*sqrt(-a*b)*x - a)/(b*x^2 + a)) - 30*(3*a^2*b^4*c - 15*a^3*
b^3*d + 35*a^4*b^2*e - 63*a^5*b*f)*x)/(a*b^8*x^4 + 2*a^2*b^7*x^2 + a^3*b^6), 1/120*(24*a*b^5*f*x^9 + 8*(5*a*b^
5*e - 9*a^2*b^4*f)*x^7 + 8*(15*a*b^5*d - 35*a^2*b^4*e + 63*a^3*b^3*f)*x^5 - 25*(3*a*b^5*c - 15*a^2*b^4*d + 35*
a^3*b^3*e - 63*a^4*b^2*f)*x^3 + 15*(3*a^2*b^3*c - 15*a^3*b^2*d + 35*a^4*b*e - 63*a^5*f + (3*b^5*c - 15*a*b^4*d
+ 35*a^2*b^3*e - 63*a^3*b^2*f)*x^4 + 2*(3*a*b^4*c - 15*a^2*b^3*d + 35*a^3*b^2*e - 63*a^4*b*f)*x^2)*sqrt(a*b)*
arctan(sqrt(a*b)*x/a) - 15*(3*a^2*b^4*c - 15*a^3*b^3*d + 35*a^4*b^2*e - 63*a^5*b*f)*x)/(a*b^8*x^4 + 2*a^2*b^7*
x^2 + a^3*b^6)]

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Sympy [A]  time = 15.8714, size = 279, normalized size = 1.35 \begin{align*} \frac{\sqrt{- \frac{1}{a b^{11}}} \left (63 a^{3} f - 35 a^{2} b e + 15 a b^{2} d - 3 b^{3} c\right ) \log{\left (- a b^{5} \sqrt{- \frac{1}{a b^{11}}} + x \right )}}{16} - \frac{\sqrt{- \frac{1}{a b^{11}}} \left (63 a^{3} f - 35 a^{2} b e + 15 a b^{2} d - 3 b^{3} c\right ) \log{\left (a b^{5} \sqrt{- \frac{1}{a b^{11}}} + x \right )}}{16} + \frac{x^{3} \left (17 a^{3} b f - 13 a^{2} b^{2} e + 9 a b^{3} d - 5 b^{4} c\right ) + x \left (15 a^{4} f - 11 a^{3} b e + 7 a^{2} b^{2} d - 3 a b^{3} c\right )}{8 a^{2} b^{5} + 16 a b^{6} x^{2} + 8 b^{7} x^{4}} + \frac{f x^{5}}{5 b^{3}} - \frac{x^{3} \left (3 a f - b e\right )}{3 b^{4}} + \frac{x \left (6 a^{2} f - 3 a b e + b^{2} d\right )}{b^{5}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**4*(f*x**6+e*x**4+d*x**2+c)/(b*x**2+a)**3,x)

[Out]

sqrt(-1/(a*b**11))*(63*a**3*f - 35*a**2*b*e + 15*a*b**2*d - 3*b**3*c)*log(-a*b**5*sqrt(-1/(a*b**11)) + x)/16 -
sqrt(-1/(a*b**11))*(63*a**3*f - 35*a**2*b*e + 15*a*b**2*d - 3*b**3*c)*log(a*b**5*sqrt(-1/(a*b**11)) + x)/16 +
(x**3*(17*a**3*b*f - 13*a**2*b**2*e + 9*a*b**3*d - 5*b**4*c) + x*(15*a**4*f - 11*a**3*b*e + 7*a**2*b**2*d - 3
*a*b**3*c))/(8*a**2*b**5 + 16*a*b**6*x**2 + 8*b**7*x**4) + f*x**5/(5*b**3) - x**3*(3*a*f - b*e)/(3*b**4) + x*(
6*a**2*f - 3*a*b*e + b**2*d)/b**5

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Giac [A]  time = 1.20482, size = 270, normalized size = 1.3 \begin{align*} \frac{{\left (3 \, b^{3} c - 15 \, a b^{2} d - 63 \, a^{3} f + 35 \, a^{2} b e\right )} \arctan \left (\frac{b x}{\sqrt{a b}}\right )}{8 \, \sqrt{a b} b^{5}} - \frac{5 \, b^{4} c x^{3} - 9 \, a b^{3} d x^{3} - 17 \, a^{3} b f x^{3} + 13 \, a^{2} b^{2} x^{3} e + 3 \, a b^{3} c x - 7 \, a^{2} b^{2} d x - 15 \, a^{4} f x + 11 \, a^{3} b x e}{8 \,{\left (b x^{2} + a\right )}^{2} b^{5}} + \frac{3 \, b^{12} f x^{5} - 15 \, a b^{11} f x^{3} + 5 \, b^{12} x^{3} e + 15 \, b^{12} d x + 90 \, a^{2} b^{10} f x - 45 \, a b^{11} x e}{15 \, b^{15}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^4*(f*x^6+e*x^4+d*x^2+c)/(b*x^2+a)^3,x, algorithm="giac")

[Out]

1/8*(3*b^3*c - 15*a*b^2*d - 63*a^3*f + 35*a^2*b*e)*arctan(b*x/sqrt(a*b))/(sqrt(a*b)*b^5) - 1/8*(5*b^4*c*x^3 -
9*a*b^3*d*x^3 - 17*a^3*b*f*x^3 + 13*a^2*b^2*x^3*e + 3*a*b^3*c*x - 7*a^2*b^2*d*x - 15*a^4*f*x + 11*a^3*b*x*e)/(
(b*x^2 + a)^2*b^5) + 1/15*(3*b^12*f*x^5 - 15*a*b^11*f*x^3 + 5*b^12*x^3*e + 15*b^12*d*x + 90*a^2*b^10*f*x - 45*
a*b^11*x*e)/b^15